document.write( "Question 513731: use factoring to solve the quadratic equation
\n" ); document.write( "x(x-2)^3 - 35(x-2)^2 =0 \n" ); document.write( "

Algebra.Com's Answer #343120 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "It is not a quadratic equation. Quadratic equations have polynomials of degree 2. This equation has a polynomial (if you multiply it out) of degree 4. It is a quartic equation. \r
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\n" ); document.write( "\n" ); document.write( "Be that as it may, since most of the difficult factoring work has been done, take two factors of

out. The difference is that the end result will have four roots instead of just two (The Fundamental Theorem of Algebra said it, I believe it, that settles it)\r
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\n" ); document.write( "\n" ); document.write( "Get rid of the inner parentheses:\r
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\n" ); document.write( "\n" ); document.write( "You can see right away that two of your roots are 2 and 2. Use the fact that -7 plus 5 is -2 and -7 times 5 is -35 to factor the quadratic term, giving you 7 and -5 as the additional two roots.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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