document.write( "Question 513707: a barge move 6km/h in still water. it travels 15 km upstream and 15 km downstream in a total time of 9 h. what is teh speed of the current \n" ); document.write( "
Algebra.Com's Answer #343111 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Time equals distance divided by rate. The downstream rate is where is the speed of the current. The upstream rate is . If we let represent the amount of time to go downstream, then must represent the amount of time to go upstream.\r
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\n" ); document.write( "\n" ); document.write( "Downstream trip:\r
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\n" ); document.write( "\n" ); document.write( "Upstream trip:\r
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\n" ); document.write( "\n" ); document.write( "Substituting:\r
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\n" ); document.write( "\n" ); document.write( "The lowest common denominator is the product of the two conjugate denominators, hence the difference of two squares:\r
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\n" ); document.write( "\n" ); document.write( "A little Algebra Music, Maestro (verification left as an exercise for the student):\r
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\n" ); document.write( "\n" ); document.write( "Solve for . Discard the negative root.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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