document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513636>Question 513636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is 12 units less than length. the perimeter is 108 units. find the length </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343109 by </B><A HREF=/tutors/aboutme.mpl?userid=umail08><B>umail08(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=umail08><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=umail08><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let:  L=Length and W=Width<BR>\n" );
document.write( "Perimeter = 2L + 2W<BR>\n" );
document.write( "W = L – 12 … width 12 units less than length<BR>\n" );
document.write( "108 = 2L + 2(L-12) <BR>\n" );
document.write( "108 =2L + 2L - 24<BR>\n" );
document.write( "108 = 4L - 24<BR>\n" );
document.write( "108 + 24 = 4L -24 + 24<BR>\n" );
document.write( "132 = 4L<BR>\n" );
document.write( "132/4 = 4L/4<BR>\n" );
document.write( "33 = L<BR>\n" );
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