document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513662>Question 513662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 100 feet. The length is 30 feet what is the area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343104 by </B><A HREF=/tutors/aboutme.mpl?userid=umail08><B>umail08(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=umail08><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=umail08><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let:  L=Length and W=Width<BR>\n" );
document.write( "Perimeter = 2L + 2W<BR>\n" );
document.write( "100ft = 2(30ft) + 2W <BR>\n" );
document.write( "100ft = 60ft + 2W<BR>\n" );
document.write( "100ft – 60ft  = 60ft – 60t + 2W<BR>\n" );
document.write( "40ft = 2W<BR>\n" );
document.write( "40ft/2 = 2W/2<BR>\n" );
document.write( "20ft = W<BR>\n" );
document.write( "Area = L x W<BR>\n" );
document.write( "Area = 30ft x 20ft<BR>\n" );
document.write( "Area = 600 sq.ft.<BR>\n" );
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