document.write( "Question 513698: Write the equation of the line that passes through the given point and is parallel or perpendicular to the given line. Write the answer in slope-intercept form.
\n" ); document.write( "(−8, 1),
\n" ); document.write( "perpendicular to
\n" ); document.write( "y + 8x = −14
\n" ); document.write( "y = \n" ); document.write( "
Algebra.Com's Answer #343103 by Maths68(1474)\"\" \"About 
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If lines are Perpendicular
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\n" ); document.write( "\n" ); document.write( "Standard Form of Equation of the line:
\n" ); document.write( "y=mx+b
\n" ); document.write( "Given
\n" ); document.write( "y + 8x = −14
\n" ); document.write( "rearrage the above equation according to the standard form
\n" ); document.write( "y=-8x-14
\n" ); document.write( "Compare above equation with the standard form equation
\n" ); document.write( "m=-8 and b=-14
\n" ); document.write( "Since lines are perpendicular multiplicatin of their slope will be (-1)
\n" ); document.write( "So slope of the required line will be (1/8)
\n" ); document.write( "Now we have a point(-8,1) and slope (1/8)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.
\n" ); document.write( "m=(y2-y1)/(x2-x1)
\n" ); document.write( "1/8=(y-1)/(x-(-8))
\n" ); document.write( "1/8=(y-1)/(x+8)
\n" ); document.write( "1(x+8)=8(y-1)
\n" ); document.write( "x+8=8y-8
\n" ); document.write( "8y-8=x+8
\n" ); document.write( "8y=x+8+8
\n" ); document.write( "8y=x+16
\n" ); document.write( "y=(x+16)/8
\n" ); document.write( "y=x/8+16/8
\n" ); document.write( "y=x/8+2
\n" ); document.write( "The standard form of the equation of the line
\n" ); document.write( "y=(1/8)x+2
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\n" ); document.write( "\n" ); document.write( "If lines are Parallel
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\n" ); document.write( "\n" ); document.write( "Standard Form of Equation of the line:
\n" ); document.write( "y=mx+b
\n" ); document.write( "Given
\n" ); document.write( "y + 8x = −14
\n" ); document.write( "rearrage the above equation according to the standard form
\n" ); document.write( "y=-8x-14
\n" ); document.write( "Compare above equation with the standard form equation
\n" ); document.write( "m=-8 and b=-14
\n" ); document.write( "Since lines are parallel their slope will be same
\n" ); document.write( "So slope of the required line will be (-8)
\n" ); document.write( "Now we have a point(-8,1) and slope (-8)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.
\n" ); document.write( "m=(y2-y1)/(x2-x1)
\n" ); document.write( "-8=(y-1)/(x-(-8))
\n" ); document.write( "-8=(y-1)/(x+8)
\n" ); document.write( "-8(x+8)=(y-1)
\n" ); document.write( "-8x-64=y-1
\n" ); document.write( "-8x-64+1=y
\n" ); document.write( "-8x-63=y
\n" ); document.write( "y=-8x-63
\n" ); document.write( "Above equatoin is the required equation of the line in standard form. \n" ); document.write( "
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