document.write( "Question 513657: a merchant has coffee worth $60 a pound that she wishes to mix with 50 pounds of coffee worth $90 a pound to get a mixture that can be sold for $70 a pound. How many pounds of the $60 coffee should be used? \n" ); document.write( "
Algebra.Com's Answer #343070 by mananth(16946)\"\" \"About 
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--------price ---------------- quantity
\n" ); document.write( "Coffee I 90 ---------------- 50 lbs
\n" ); document.write( "coffee II 60 ---------------- x lbs
\n" ); document.write( "Mixture 70 ---------------- 50 + x lbs
\n" ); document.write( "
\n" ); document.write( "90*50+60 x=70(50 +x)
\n" ); document.write( "4500+60 x=3500 + 70 x
\n" ); document.write( "60 x + -70 x = 3500 - -4500
\n" ); document.write( "-10 x = -1000
\n" ); document.write( "/ -10
\n" ); document.write( "x = 100
\n" ); document.write( " 100 lbs of 60 % coffee II
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