document.write( "Question 513644: a certain metal is 30% tin. how many kilograms of this metal must be mixed with 70 kg of a metal that is 70% tin to get a metal that is 50% tin? \n" ); document.write( "
Algebra.Com's Answer #343069 by mananth(16946)![]() ![]() You can put this solution on YOUR website! --------percent ---------------- quantity \n" ); document.write( "Tin I 70 ---------------- 70 Kgs \n" ); document.write( "Tin II 30 ---------------- x Kgs \n" ); document.write( "Mixture 50 ---------------- 70 + x Kgs \n" ); document.write( " \n" ); document.write( "70*70+30 x= 50 ( 70 + x ) \n" ); document.write( "4900 + 30x = 3500 + 50 x \n" ); document.write( "30 x + -50 x = 3500 - -4900 \n" ); document.write( "-20 x = -1400 \n" ); document.write( "/ -20 \n" ); document.write( "x = 70 \n" ); document.write( " 70 Kgs of 30 % Tin II \n" ); document.write( " \n" ); document.write( " |