document.write( "Question 513644: a certain metal is 30% tin. how many kilograms of this metal must be mixed with 70 kg of a metal that is 70% tin to get a metal that is 50% tin? \n" ); document.write( "
Algebra.Com's Answer #343069 by mananth(16946)\"\" \"About 
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--------percent ---------------- quantity
\n" ); document.write( "Tin I 70 ---------------- 70 Kgs
\n" ); document.write( "Tin II 30 ---------------- x Kgs
\n" ); document.write( "Mixture 50 ---------------- 70 + x Kgs
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\n" ); document.write( "70*70+30 x= 50 ( 70 + x )
\n" ); document.write( "4900 + 30x = 3500 + 50 x
\n" ); document.write( "30 x + -50 x = 3500 - -4900
\n" ); document.write( "-20 x = -1400
\n" ); document.write( "/ -20
\n" ); document.write( "x = 70
\n" ); document.write( " 70 Kgs of 30 % Tin II
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