document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513637>Question 513637</A>: <I><SPAN STYLE=\"word-break: break-all;\"> single logarithm:\r<BR>\n" );
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document.write( "1.) 1/2ln1/2-ln2+ln5+ln12\r<BR>\n" );
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document.write( "2.) 3/2log6-1/2log3-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343066 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.) 1/2ln1/2-ln2+ln5+ln12<BR>\n" );
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document.write( "= ln(sqrt(1/2)) + ln[5*12/2]<BR>\n" );
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document.write( "= ln[30*sqrt(1/2)]<BR>\n" );
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document.write( "2.) 3/2log6-1/2log3-4<BR>\n" );
document.write( "log(6^(3/2) - log(3^(1/2) - 4<BR>\n" );
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document.write( "= log[(6^3/2)/3^(1/2)] - 4<BR>\n" );
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document.write( "= log [(3*2)^(3/2)/3^(1/2)] - 4<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= log[9*2^(3/2)]-4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "========\r<BR>\n" );
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document.write( " </SPAN>\n" );
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