document.write( "Question 513620: find the missing coordinates 2x-3y=6:(3, ), ( ,-2), (-1, ), ( ,2) \n" ); document.write( "
Algebra.Com's Answer #343062 by umail08(87)\"\" \"About 
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Find the missing coordinates 2x-3y=6:(3, ), ( ,-2), (-1, ), ( ,2)
\n" ); document.write( "2x-3y=6: (3,0), (0 ,-2), (-1, -8/3), (6,2)
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\n" ); document.write( "If x=3, then:
\n" ); document.write( "2(3) – 3y = 6
\n" ); document.write( "6 – 3y = 6
\n" ); document.write( "-3y = 6 – 6
\n" ); document.write( "-3y = 0
\n" ); document.write( "-3y/-3 = 0/-3
\n" ); document.write( "y = 0 \r
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\n" ); document.write( "\n" ); document.write( "If x = -1, then:
\n" ); document.write( "2(-1) – 3y = 6
\n" ); document.write( "-2 – 3y = 6
\n" ); document.write( "-3y = 6 +2
\n" ); document.write( "-3y = 8
\n" ); document.write( "-3y/-3 = 8/-3
\n" ); document.write( "y = -8/3
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\n" ); document.write( "\n" ); document.write( " If y=-2, then:
\n" ); document.write( "2x – 3(-2) = 6
\n" ); document.write( "2x + 6 = 6
\n" ); document.write( "2x = 6 - 6
\n" ); document.write( "2x = 0
\n" ); document.write( "2x/2 = 0/2
\n" ); document.write( "x = 0\r
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\n" ); document.write( "\n" ); document.write( "If y=2, then:
\n" ); document.write( "2x – 3(2) = 6
\n" ); document.write( "2x - 6 = 6
\n" ); document.write( "2x = 6 + 6
\n" ); document.write( "2x = 12
\n" ); document.write( "2x/2 = 12/2
\n" ); document.write( "x = 6\r
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