document.write( "Question 512888: TWO PERSONS R AND S HAD TO MEET AT A PLACE 36KM FROM WHERE TEY WERE AT THAT MOMENT. S,WHO WAS GIVEN A HEAD START OF 2HOURS, REACHED THE DESTINATION 12MIN EARLIER THAN R. IF R TRAVELED 18KMPH FASTER THAN S, AT WHAT SPEED DID R TRAVEL? \n" ); document.write( "
Algebra.Com's Answer #343055 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! TWO PERSONS R AND S HAD TO MEET AT A PLACE 36KM FROM WHERE THEY WERE AT THAT MOMENT. \n" ); document.write( "S, WHO WAS GIVEN A HEAD START OF 2HOURS, REACHED THE DESTINATION 12 MIN EARLIER THAN R. \n" ); document.write( " IF R TRAVELED 18KMPH FASTER THAN S, AT WHAT SPEED DID R TRAVEL? \n" ); document.write( ": \n" ); document.write( "Change 12 min: 12/60 = .2 hrs \n" ); document.write( ": \n" ); document.write( "Let r = R's speed \n" ); document.write( "then \n" ); document.write( "(r-18) = S's speed \n" ); document.write( ": \n" ); document.write( "Write time equation \n" ); document.write( "r's time + .2 hrs = s's time - 2 hrs \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply both sides by r(r-18), resulting in \n" ); document.write( "36(r-18) = 36r - 2.2r(r-18) \n" ); document.write( "36r - 648 = 36r - 2.2r^2 + 39.6r \n" ); document.write( "36r's cancel write a quadratic equation \n" ); document.write( "2.2r^2 - 39.6r - 648 = 0 \n" ); document.write( "Use the quadratic formula: a=2.2, b=-39.6, c=-648 \n" ); document.write( "the positive solution: r = 28.38 km/hr \n" ); document.write( " |