document.write( "Question 512888: TWO PERSONS R AND S HAD TO MEET AT A PLACE 36KM FROM WHERE TEY WERE AT THAT MOMENT. S,WHO WAS GIVEN A HEAD START OF 2HOURS, REACHED THE DESTINATION 12MIN EARLIER THAN R. IF R TRAVELED 18KMPH FASTER THAN S, AT WHAT SPEED DID R TRAVEL? \n" ); document.write( "
Algebra.Com's Answer #343055 by ankor@dixie-net.com(22740)\"\" \"About 
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TWO PERSONS R AND S HAD TO MEET AT A PLACE 36KM FROM WHERE THEY WERE AT THAT MOMENT.
\n" ); document.write( "S, WHO WAS GIVEN A HEAD START OF 2HOURS, REACHED THE DESTINATION 12 MIN EARLIER THAN R.
\n" ); document.write( " IF R TRAVELED 18KMPH FASTER THAN S, AT WHAT SPEED DID R TRAVEL?
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\n" ); document.write( "Change 12 min: 12/60 = .2 hrs
\n" ); document.write( ":
\n" ); document.write( "Let r = R's speed
\n" ); document.write( "then
\n" ); document.write( "(r-18) = S's speed
\n" ); document.write( ":
\n" ); document.write( "Write time equation
\n" ); document.write( "r's time + .2 hrs = s's time - 2 hrs
\n" ); document.write( "\"36%2Fr\" + .2 = \"36%2F%28%28r-18%29%29\" - 2
\n" ); document.write( "\"36%2Fr\" = \"36%2F%28%28r-18%29%29\" - 2 -.2
\n" ); document.write( "\"36%2Fr\" = \"36%2F%28%28r-18%29%29\" - 2.2
\n" ); document.write( "multiply both sides by r(r-18), resulting in
\n" ); document.write( "36(r-18) = 36r - 2.2r(r-18)
\n" ); document.write( "36r - 648 = 36r - 2.2r^2 + 39.6r
\n" ); document.write( "36r's cancel write a quadratic equation
\n" ); document.write( "2.2r^2 - 39.6r - 648 = 0
\n" ); document.write( "Use the quadratic formula: a=2.2, b=-39.6, c=-648
\n" ); document.write( "the positive solution: r = 28.38 km/hr
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