document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513617>Question 513617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It took John 2 hours to bike from Dublin to Pickerington at a constant speed. The return trip took only 1.5 hours because he increased his speed by 6 mph. How far apart are Dublin and Pickerington? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343054 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It took John 2 hours to bike from Dublin to Pickerington at a constant speed. The return trip took only 1.5 hours because he increased his speed by 6 mph. How far apart are Dublin and Pickerington?<BR>\n" );
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document.write( "Let d = the distance from D to P<BR>\n" );
document.write( "The speed of the outbound trip is:<BR>\n" );
document.write( "s = d/2 [D -> P takes 2 h]<BR>\n" );
document.write( "The speed of the return trip is:<BR>\n" );
document.write( "s + 6 = d/1.5 [P -> D takes 1.5 h; speed increased 6 mph]<BR>\n" );
document.write( "Substitute the value for s in the 1st equation into the 2nd equation:<BR>\n" );
document.write( "d/2 + 6 = d/1.5<BR>\n" );
document.write( "Solve for d:<BR>\n" );
document.write( "(2d - 1.5d)/3 = 6<BR>\n" );
document.write( "d = 36 mi </SPAN>\n" );
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