document.write( "Question 513621: a mother is twice as old as her daughter now. sixteen years ago,she was four times as old. how old is each now?
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Algebra.Com's Answer #343053 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of mother = m \n" ); document.write( "Present age of daughter = d\r \n" ); document.write( "\n" ); document.write( "Mother is twice as old as her daughter now. \n" ); document.write( "m=2d.......(1) \n" ); document.write( "sixteen years ago,she was four times as old \n" ); document.write( "m-16=4(d-16) \n" ); document.write( "m-16=4d-64 \n" ); document.write( "m=4d-64+16 \n" ); document.write( "m=4d-48.........(2) \n" ); document.write( "subtitute the value of m from (1) to (2) \n" ); document.write( "2d=4d-48 \n" ); document.write( "2d-4d=-48 \n" ); document.write( "-2d=-48 \n" ); document.write( "-2d/-2=-48/-2 \n" ); document.write( "d=24 \n" ); document.write( "Put the value of d in (1) \n" ); document.write( "m=2d \n" ); document.write( "m=2*24 \n" ); document.write( "m=48 \n" ); document.write( "resent age of mother = m = 48 years old \n" ); document.write( "Present age of daughter = d = 24 years old \n" ); document.write( " \n" ); document.write( " |