document.write( "Question 513574: use factoring to solve the quadratic equation
\n" ); document.write( "x(x-2)^3 - 35(x-2)^2 =0
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Algebra.Com's Answer #343043 by mananth(16946)\"\" \"About 
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x(x-2)^3-35(x-2)^2=0\r
\n" ); document.write( "\n" ); document.write( "x(x-2)^3=35(x-2)^2\r
\n" ); document.write( "\n" ); document.write( "divide by (x-2)^2
\n" ); document.write( "x(x-2)=35
\n" ); document.write( "x^2-2x=35
\n" ); document.write( "x^2-2x-35=0
\n" ); document.write( "x^2-7x+5x-35=0
\n" ); document.write( "x(x-7)+5(x-7)=0
\n" ); document.write( "(x-7)(x+5)=0
\n" ); document.write( "x=7 OR -5
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