document.write( "Question 513398: How many liters each of a 15% antifreeze solution and a 30% antifreeze solution must be mixed to make 6 liters of a 20% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #343041 by Maths68(1474)\"\" \"About 
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Solution A
\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration =15% =0.15
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\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 6-x
\n" ); document.write( "Concentration =30% = 0.3
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\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount =6
\n" ); document.write( "Concentration =20%=0.2
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\n" ); document.write( "Solution B
\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant
\n" ); document.write( "(x)(0.15)+(6-x)(0.3)=(6)(0.2)
\n" ); document.write( "0.15x+1.8-0.3x=1.2
\n" ); document.write( "0.15x-0.3x=1.2-1.8
\n" ); document.write( "-0.15x=-0.6
\n" ); document.write( "-0.15x/-0.15=-0.6/-0.15
\n" ); document.write( "x=4\r
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\n" ); document.write( "Solution A
\n" ); document.write( "Amount = x=4 liters
\n" ); document.write( "Concentration =15% =0.15
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\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 6-x =6-4=2 liters
\n" ); document.write( "Concentration =30% = 0.3\r
\n" ); document.write( "\n" ); document.write( "===============================================================================
\n" ); document.write( "4 liters of a 15% antifreeze solution and 2 liters of 30% antifreeze solution must be mixed to make 6 liters of a 20% antifreeze solution.
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