document.write( "Question 513472: AN alloy containing 40% gold and an alloy containing 70% gold are to be mixed to produce 50 pounds of an alloy containing 60% gold. How much of each alloy is needed? \n" ); document.write( "
Algebra.Com's Answer #343040 by Maths68(1474)\"\" \"About 
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Alloy A
\n" ); document.write( "Amount = x lb
\n" ); document.write( "Concentration =40% =0.4
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\n" ); document.write( "Alloy B
\n" ); document.write( "Amount = 50-x lb
\n" ); document.write( "Concentration =70% = 0.70
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\n" ); document.write( "Final Alloy
\n" ); document.write( "Amount =50 lb
\n" ); document.write( "Concentration =60%=0.6
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\n" ); document.write( "[Amount Alloy A * Concentration A] + [Amount Alloy B * Concentration of B] = Amount of Final Alloy * Concentration of Final Alloy
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\n" ); document.write( "(x)(0.4)+(50-x)(0.7)=(50)(0.6)
\n" ); document.write( "0.4x+35-0.7x=30
\n" ); document.write( "0.4x-0.7x=30-35
\n" ); document.write( "-0.3x=-5
\n" ); document.write( "-0.3x/-0.3=-5/-0.3
\n" ); document.write( "x=16.66
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\n" ); document.write( "Alloy A
\n" ); document.write( "Amount = 16.66 lb
\n" ); document.write( "Concentration =40% =0.4
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\n" ); document.write( "Alloy B
\n" ); document.write( "Amount = 50-16.66=33.33 lb
\n" ); document.write( "Concentration =70% = 0.70
\n" ); document.write( "==============================
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\n" ); document.write( "A 16.66 pounds alloy containing 40% gold and a 33.33 pounds alloy containing 70% gold are to be mixed to produce 50 pounds of an alloy containing 60% gold
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