document.write( "Question 513554: A goldsmith mixed 10 grams of a 50% gold alloy with 40 grams of 15% gold alloy. What is the percent concentration of the resulting alloy? \n" ); document.write( "
Algebra.Com's Answer #343039 by Maths68(1474)\"\" \"About 
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Alloy A
\n" ); document.write( "Amount = 10 grams
\n" ); document.write( "Concentration =50% =0.5
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\n" ); document.write( "Alloy B
\n" ); document.write( "Amount = 40
\n" ); document.write( "Concentration =15% = 0.15
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\n" ); document.write( "Final Alloy
\n" ); document.write( "Amount =50
\n" ); document.write( "Concentration =x
\n" ); document.write( "==================================
\n" ); document.write( "[Amount Alloy A * Concentration A] + [Amount Alloy B * Concentration of B] = Amount of Final Alloy * Concentration of Final Alloy
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\n" ); document.write( "(10)(0.5)+(10)(0.15)=(50)(x)
\n" ); document.write( "5+1.5=50x
\n" ); document.write( "6.5=50x
\n" ); document.write( "6.5/50=50x/50
\n" ); document.write( "0.13=x
\n" ); document.write( "x=0.13
\n" ); document.write( "x=13/100=13%
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\n" ); document.write( "A goldsmith mixed 10 grams of a 50% gold alloy with 40 grams of 15% gold alloy which will result in 50 grams of a 13% gold alloy.
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