document.write( "Question 513184: Find three consecutive even integers for which -4 times the sum of the first and the third integers is 192. \n" ); document.write( "
Algebra.Com's Answer #343032 by Maths68(1474)\"\" \"About 
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Find three consecutive even integers for which -4 times the sum of the first and the third integers is 192.\r
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\n" ); document.write( "\n" ); document.write( "Let
\n" ); document.write( "1st Interger = x+2
\n" ); document.write( "2nd Interger = x+4
\n" ); document.write( "3rd Integer = x+6\r
\n" ); document.write( "\n" ); document.write( "-4*(1st Integer + 3rd Integer) = 192
\n" ); document.write( "-4(x+2+x+6)=192
\n" ); document.write( "-4(2x+8)=192
\n" ); document.write( "-8x-32=192
\n" ); document.write( "-8x=192+32
\n" ); document.write( "-8x=224
\n" ); document.write( "-8x/-8=224/-8
\n" ); document.write( "x=-28\r
\n" ); document.write( "\n" ); document.write( "1st Interger = x+2 = -28+2=-26
\n" ); document.write( "2nd Interger = x+4 = -28+4=-24
\n" ); document.write( "3rd Integer = x+6 = -24+6=-22\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "-4*(1st Integer + 3rd Integer) = 192
\n" ); document.write( "-4*(-26 + (-22)) = 192
\n" ); document.write( "-4*(-26-22) = 192
\n" ); document.write( "-4*(-48) = 192
\n" ); document.write( "192=192\r
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