document.write( "Question 513520: johnny is 24 years old, which is three years less than 3 times joeys age.
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Algebra.Com's Answer #343028 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Johnny Present age = j
\n" ); document.write( "Joeys Present age = k\r
\n" ); document.write( "\n" ); document.write( "Johnny is 24 years old means we have to add 24 to the present age of Joeys to equalize their ages
\n" ); document.write( "j=k+24............(1)\r
\n" ); document.write( "\n" ); document.write( "which is three years less than 3 times Joeys age
\n" ); document.write( "Johnny Present age = 3 times Joeys age - 3
\n" ); document.write( "j=3k-3............(2)\r
\n" ); document.write( "\n" ); document.write( "Put the value of j from (1) to (2)
\n" ); document.write( "k+24=3k-3
\n" ); document.write( "k-3k=-3-24
\n" ); document.write( "-2k=-27
\n" ); document.write( "-2k/-2=-27/2
\n" ); document.write( "k=13.5
\n" ); document.write( "Put the value of k in (1)
\n" ); document.write( "j=k+24
\n" ); document.write( "j=13.5+24
\n" ); document.write( "j=37.5\r
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\n" ); document.write( "\n" ); document.write( "Johnny Present age = j = 37 and half years old
\n" ); document.write( "Joeys Present age = k = 13 and half years old\r
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