document.write( "Question 513518: the sum of three numbers is 45. one number is five more than the second number. it is also twice the third. find the numbers. \n" ); document.write( "
Algebra.Com's Answer #343026 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let 1st number be F
\n" ); document.write( "Then second = F – 5
\n" ); document.write( "Also, third = ½F\r
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\n" ); document.write( "\n" ); document.write( "We then have: F + F – 5 + ½F = 45
\n" ); document.write( "2½F – 5 = 45
\n" ); document.write( "2½F = 45 + 5
\n" ); document.write( "2½F = 50
\n" ); document.write( "5F/2 = 50
\n" ); document.write( "5F = 100 ----- Cross-multiplying
\n" ); document.write( "F, or 1st number = 100/5, or \"highlight_green%2820%29\"\r
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\n" ); document.write( "\n" ); document.write( "2nd number = F – 5, or 20 – 5, or \"highlight_green%2815%29\"\r
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\n" ); document.write( "\n" ); document.write( "3rd number = ½F, or ½(20), or \"highlight_green%2810%29\" \r
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\n" ); document.write( "\n" ); document.write( "-------
\n" ); document.write( "Check
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\n" ); document.write( "First + second + third = 45\r
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\n" ); document.write( "\n" ); document.write( "20 + 15 + 10 = 45 \r
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\n" ); document.write( "\n" ); document.write( "45 = 45 (TRUE)\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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