document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513449>Question 513449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, can you help me please with this equation?\r<BR>\n" );
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document.write( "Square root of (3x+10) = x+2<BR>\n" );
document.write( "Upon solving, I got x= -3 and x= 2. <BR>\n" );
document.write( "When I plugged in the roots, I did not get the check for x= -3. I got<BR>\n" );
document.write( "Square root of (-9+10) = -3+2<BR>\n" );
document.write( "1 = -1 which is FALSE; thus, x = -3 is NOT the solution. And only x = 2 is the solution. Is that right or not? Please help me answer this question and tell me if x = -3 is or is NOT the solution? \r<BR>\n" );
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document.write( "Thank you so much. \r<BR>\n" );
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document.write( "I.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343021 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343021\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (-1)^2 = 1\r<BR>\n" );
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document.write( "sqrt(1) = ±1\r<BR>\n" );
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document.write( "both of your solutions work </SPAN>\n" );
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