document.write( "Question 6394: Please assist me in comprehending how to solve this problem.\r
\n" ); document.write( "\n" ); document.write( "Find the solution of the system y = x^2 + 5 and y = 2x + 4
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Algebra.Com's Answer #3430 by xcentaur(357)\"\" \"About 
You can put this solution on YOUR website!
y = x^2 + 5
\n" ); document.write( "y = 2x + 4
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\n" ); document.write( "Therefore,
\n" ); document.write( "x^2 + 5 = 2x + 4
\n" ); document.write( "x^2 - 2x + 5 - 4 = 0
\n" ); document.write( "x^2 - 2x + 1 = 0
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-2x%2B1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-2%29%5E2-4%2A1%2A1=0\".
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\n" ); document.write( " Discriminant d=0 is zero! That means that there is only one solution: \"x+=+%28-%28-2%29%29%2F2%5C1\".
\n" ); document.write( " Expression can be factored: \"1x%5E2%2B-2x%2B1+=+1%28x-1%29%2A%28x-1%29\"
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\n" ); document.write( " Again, the answer is: 1, 1.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-2%2Ax%2B1+%29\"

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\n" ); document.write( "Therefore,x=1
\n" ); document.write( "then y=2x+4=2+4=6
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\n" ); document.write( "x=1,y=6

\n" ); document.write( "Hope this helps,
\n" ); document.write( "good luck \n" ); document.write( "

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