document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140>Question 1140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to find the value of v in the following log.<BR>\n" );
document.write( "    v=log(base 2)(1/4)<BR>\n" );
document.write( "If I do as the law says, I come up with -2.  But the book is showing 22.  Am I doing this wrong or is the books answer wrong. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If v=log(base 2)(1/4), by definition of log,<BR>\n" );
document.write( " 2^v = 4.<BR>\n" );
document.write( " Now if v= -2, 2^(-2) = 1/2^2 = 1/4<BR>\n" );
document.write( " So your answer is correct.\r<BR>\n" );
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document.write( " One way to solve:<BR>\n" );
document.write( " v = log(base 2)(1/4) = -log(base 2)4 =  -log(base 2) 2^2<BR>\n" );
document.write( " =  - 2 log(base 2) 2 = -2 * 1 = -2.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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