document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513410>Question 513410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the third angle.\r<BR>\n" );
document.write( "\n" );
document.write( "y degrees, (y-20)degrees, _______________ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342998 by </B><A HREF=/tutors/aboutme.mpl?userid=umail08><B>umail08(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=umail08><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=umail08><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the angles of a triangle is 180 degrees, so:<BR>\n" );
document.write( "Let Angle A = y degrees, Angle B = (y-20) degrees, Angle C = unknown <BR>\n" );
document.write( "Angle A + angle B + Angle C = 180 degrees<BR>\n" );
document.write( "Y + Y - 20 + Angle C = 180<BR>\n" );
document.write( "    2y – 20 + Angle C = 180 <BR>\n" );
document.write( "                      Angle C = 180 + 20  – 2y<BR>\n" );
document.write( "                      Angle C = 200 – 2y <BR>\n" );
document.write( "&#8195;<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );