document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513390>Question 513390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This one is too hard and I can't get it. . .\r<BR>\n" );
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document.write( "Find the exact value of:<BR>\n" );
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document.write( "cos ( tan^-1 (4/3) + cos^-1 (12/13 ) )<BR>\n" );
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document.write( "Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342989 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cos (A + B) = (cos A)cos B - (sin A)sin B\r<BR>\n" );
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document.write( "for a 3-4-5 triangle ___ tan^-1 (4/3) = cos^-1 (3/5) = sin^-1 (4/5)\r<BR>\n" );
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document.write( "for a 5-12-13 triangle ___ cos^-1 (12/13) = sin^-1 (5/13) </SPAN>\n" );
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