document.write( "Question 513088: 0.06x+0.09(x+200)=63 \n" ); document.write( "
Algebra.Com's Answer #342872 by umail08(87) You can put this solution on YOUR website! 0.06x + 0.09(x+200) = 63 \n" ); document.write( "0.06x + 0.09x + 18 = 63 \n" ); document.write( "0.15x + 18 = 63 \n" ); document.write( "0.15x + 18 – 18 = 63 -18 \n" ); document.write( "0.15x = 45 \n" ); document.write( " 0.15x/0.15 = 45/0.15 \n" ); document.write( " x = 300 \n" ); document.write( " |