document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513038>Question 513038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the perimeter of a triangle if one side is 10 feet, another side is one-third the perimeter, and the third side is half the perimeter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342871 by </B><A HREF=/tutors/aboutme.mpl?userid=umail08><B>umail08(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=umail08><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=umail08><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = sum of the sides<BR>\n" );
document.write( "x = a + b + c     x represents the perimeter<BR>\n" );
document.write( "x=10ft + 1/3x +1/2x<BR>\n" );
document.write( "-10ft + x = 10ft – 10ft + 1/3x +1/2x<BR>\n" );
document.write( "-10ft + x –x =-x+1/3x+1/2x<BR>\n" );
document.write( "-10ft = -6/6x+2/6x+3/6x<BR>\n" );
document.write( " -10ft = -1/6x<BR>\n" );
document.write( "-6(-10ft) = -6(-1/6x)<BR>\n" );
document.write( "  60ft = x  .. therefore the perimeter is 60ft.\r<BR>\n" );
document.write( "\n" );
document.write( "Check:<BR>\n" );
document.write( "x=10ft + 1/3x +1/2x<BR>\n" );
document.write( "60ft = 10ft + 1/3(60ft) + ½(60ft)<BR>\n" );
document.write( "60ft = 10ft + 20ft + 30ft<BR>\n" );
document.write( "60ft = 60ft<BR>\n" );
document.write( " </SPAN>\n" );
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