document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513033>Question 513033</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equation of a line in Standard Form perpendicular to Y=2x-1 passing through the point (2,-3)\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342861 by </B><A HREF=/tutors/aboutme.mpl?userid=umail08><B>umail08(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=umail08><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=umail08><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342861\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slopes of Perpendicular lines are the negative reciprocal of each other.<BR>\n" );
document.write( "If the line is perpendicular to:  y = 2x -1 then the slope would be -1/2<BR>\n" );
document.write( "Using the point-slope formula:<BR>\n" );
document.write( "Slope: -1/2 and point: (2,-3)  ..note point is represented as (x1,y1)<BR>\n" );
document.write( "y-y1 =m(x-x1)<BR>\n" );
document.write( "y –(-3) = -1/2(x-2)<BR>\n" );
document.write( "y+3 = -1/2x + 1<BR>\n" );
document.write( "y+3-3 = -1/2x +1-3<BR>\n" );
document.write( "y = -1/2 -2<BR>\n" );
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