document.write( "Question 512980: How many liters of a 60% solution should be added to 50 liters of a 30% solution to obtain a 40% solution? \n" ); document.write( "

Algebra.Com's Answer #342838 by Maths68(1474) $\"\"$ $\"About$

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Soluton A
\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration = 60%=0.6
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\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 50 liters
\n" ); document.write( "Concentration = 30%=0.3
\n" ); document.write( "================================================================================
\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount=50+x
\n" ); document.write( "Concentration=40%=0.4
\n" ); document.write( "================================================================================
\n" ); document.write( "(Amount of A * Concentration of A)+(Amount of B * Concentration of B) = (Amount of Resultant * Concentration of Resultant)
\n" ); document.write( "(x*0.6)+(50*0.3)=(50+x)*0.40
\n" ); document.write( "0.6x+15=20+0.4x
\n" ); document.write( "0.6x-0.4x=20-15
\n" ); document.write( "0.2x=5
\n" ); document.write( "0.2x/0.2=5/0.2
\n" ); document.write( "x=50
\n" ); document.write( "================================================================================
\n" ); document.write( "50 liters of a 60% solution should be added to 50 liters of a 30% solution to obtain a 40% solution? \n" ); document.write( "

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