document.write( "Question 51339: Please help me with this one. I am in no way good at this but I am trying to keep from asking for help, thank!\r
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document.write( "Solve each of the following systems by substitution.
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document.write( " 5x - 2y = -5
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document.write( " y - 5x = 3 \n" );
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Algebra.Com's Answer #34282 by chuy605(1)![]() ![]() ![]() You can put this solution on YOUR website! 1st chose an easy equation like: Y-5x=3\r \n" ); document.write( "\n" ); document.write( "and move the -5x to the right side so you get Y=5x+3\r \n" ); document.write( "\n" ); document.write( "then you re-place Y with (5x+3) in the 2nd equation \r \n" ); document.write( "\n" ); document.write( "and you get this 5x-2(5x+3)=-5\r \n" ); document.write( "\n" ); document.write( "5x-10x-6=-5 \n" ); document.write( "-5x-6+6=-5+6 \n" ); document.write( "-5x=1 \n" ); document.write( "x=-1/5\r \n" ); document.write( "\n" ); document.write( "just re-place the x to 5(-1/5)-2y=-5 to get Y\r \n" ); document.write( "\n" ); document.write( "-1-2y=-5 \n" ); document.write( "-2y=-4 \n" ); document.write( "Y=2\r \n" ); document.write( "\n" ); document.write( "check\r \n" ); document.write( "\n" ); document.write( "5(-1/5)-2(2)=-5 \n" ); document.write( "-1-4=-5 \n" ); document.write( "-5=-5 \n" ); document.write( " |