document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=512933>Question 512933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An airplane travels 150km/h for 2 hours at 138 degrees from Omaha. How far south is the plane from Omaha after those two hours? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342818 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An airplane travels 150km/h for 2 hours at 138 degrees from Omaha. How far south is the plane from Omaha after those two hours?<BR>\n" );
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document.write( "Note: I'm assuming zero degrees is due North from Omaha so the<BR>\n" );
document.write( "trig angle followed by the plane is really -48 degrees (4th Quadrant).<BR>\n" );
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document.write( "Draw the picture.<BR>\n" );
document.write( "The plane has gone 2*150 = 300 km<BR>\n" );
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document.write( "The south component of its flight = 150cos(-48) = 150*0.6691 = 100.37 km<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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