document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51339>Question 51339</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this one. I am in no way good at this but I am trying to keep from asking for help, thank!\r<BR>\n" );
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document.write( "Solve each of the following systems by substitution.<BR>\n" );
document.write( "            5x - 2y =  -5<BR>\n" );
document.write( "                  y - 5x = 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34281 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34281\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To do this by substitution, the first step is to solve for one of the variables in terms of the other.  The easiest one to solve for is the y in the second equation.  Do this by adding +5x to each side of the equation.\r<BR>\n" );
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document.write( "y = 5x + 3\r<BR>\n" );
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document.write( "Now, subsitute this into the first equation:<BR>\n" );
document.write( "5x - 2y = -5<BR>\n" );
document.write( "5x - 2(_____) = -5<BR>\n" );
document.write( "5x - 2(5x+3) = -5\r<BR>\n" );
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document.write( "5x - 10x - 6 = -5<BR>\n" );
document.write( "-5x - 6 = -5<BR>\n" );
document.write( "-5x-6+6=-5+6<BR>\n" );
document.write( "-5x=1<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=-1%2F5 ALIGN=MIDDLE  ALT=\"x=-1%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Substitute back into the equation in which you solved for y:<BR>\n" );
document.write( "y=5x+3<BR>\n" );
document.write( "y=5(-1/5)+3<BR>\n" );
document.write( "y=-1+3= 2\r<BR>\n" );
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document.write( "The solution is (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F5 ALIGN=MIDDLE  ALT=\"-1%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >,2) \r<BR>\n" );
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document.write( "Also, see my website by clicking on my tutor name \"rapaljer\" anywhere in algebra.com, and look for \"Math in Living Color,\" then Intermediate Algebra, and look for Section 5.02, Systems of Inequalities.  There are LOTS of problems solved in Living Color!!\r<BR>\n" );
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document.write( "R^2 at SCC\r<BR>\n" );
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document.write( " </SPAN>\n" );
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