document.write( "Question 512669: On a 50 mile bike ride Irena averaged 4 mph faster for the first 36 miles than she did for the last 14 miles. The entire trop took 3 hours. Find her speed for the 36 miles \n" ); document.write( "
Algebra.Com's Answer #342809 by ankor@dixie-net.com(22740)\"\" \"About 
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On a 50 mile bike ride Irena averaged 4 mph faster for the first 36 miles than she did for the last 14 miles.
\n" ); document.write( " The entire trip took 3 hours. Find her speed for the 36 miles
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\n" ); document.write( "let s = the speed for the 1st 36 mi
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\n" ); document.write( "Write a time equation; time = dist/speed
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\n" ); document.write( "36mi time + 14 mi time = 3 hrs
\n" ); document.write( "\"36%2Fs\" + \"14%2F%28%28s-4%29%29\" = 3
\n" ); document.write( "Multiply by s(s-4)
\n" ); document.write( "s(s-4)*\"36%2Fs\" + s(s-4)*\"14%2F%28%28s-4%29%29\" = s(s-4)*3
\n" ); document.write( "cancel the denominators
\n" ); document.write( "36(s-4) + 14s = 3s(s-4)
\n" ); document.write( "36s - 144 + 14s = 3x^2 - 12s
\n" ); document.write( "50s - 144 = 3x^2 - 12s
\n" ); document.write( "arrange as a quadratic equation on the right
\n" ); document.write( "0 = 3s^2 - 12s - 50s + 144
\n" ); document.write( "3x^2 - 62s + 144 = 0
\n" ); document.write( "you can use the quadratic formula, but this will factor to:
\n" ); document.write( "(3s-8)(s-18) = 0
\n" ); document.write( "The reasonable solution
\n" ); document.write( "s = 18 mph for the 1st 36 mi
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\n" ); document.write( "Check this by finding the time at each speed
\n" ); document.write( "36/18 = 2 hrs
\n" ); document.write( "14/14 = 1 hr
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