document.write( "Question 51340: solve by completing the square show work for credit\r
\n" ); document.write( "\n" ); document.write( "2x^2+6x-2=0\r
\n" ); document.write( "\n" ); document.write( "please solve, thanks.
\n" ); document.write( "

Algebra.Com's Answer #34280 by darq(90)\"\" \"About 
You can put this solution on YOUR website!
2x^2+6x-2=0
\n" ); document.write( "first eliminate (x^2)'s coefficient by dividing both sides with 2
\n" ); document.write( "x^2+3x-1=0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "then take x's coefficient (3) divide it with 2 now you have one and a half \"3%2F2\". and take \"3%2F2\"'s square we have \"9%2F4\". so in order to have a perfect square we need to convert (-1) to \"9%2F4\". we will do it by adding 1 + \"9%2F4\" to each side which is equal to \"13%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x%2B%289%2F4%29=13%2F4\"
\n" ); document.write( "(x+(3/2))^2=13/4
\n" ); document.write( "\"x%2B%283%2F2%29=+%2B-+sqrt+%2813%2F4%29\"
\n" ); document.write( "\"x=%28+%2B-+sqrt%2813%29+%2F2%29-%283%2F2%29\"
\n" ); document.write( "\"x=%28+%2B-+sqrt%2813%29+-3%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "now we will find two possible answers;\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=%28%2Bsqrt%2813%29-3%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-sqrt%2813%29-3%29%2F2\"
\n" ); document.write( "
\n" );