document.write( "Question 512911: From a large number of actuarial exam scores, a random sample of 250 scores is selected, and it is found that 177 of these 250 are passing scores. Based on this sample, find a 90% confidence interval for the proportion of all scores that are passing. Then complete the table below.\r
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document.write( "Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places.\r
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document.write( "What is the lower limit of the 90% confidence interval?
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document.write( "What is the upper limit of the 90% confidence interval? \n" );
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Algebra.Com's Answer #342785 by stanbon(75887) ![]() You can put this solution on YOUR website! From a large number of actuarial exam scores, a random sample of 250 scores is selected, and it is found that 177 of these 250 are passing scores. \n" ); document.write( "-------------------------- \n" ); document.write( "Based on this sample, find a 90% confidence interval for the proportion of all scores that are passing. Then complete the table below. \n" ); document.write( "-------------------------- \n" ); document.write( "p-hat = 177/250 = 0.708 \n" ); document.write( "ME = 1.645*sqrt[0.708*0.292/250] = 0.047 \n" ); document.write( "------------------ \n" ); document.write( " \n" ); document.write( "Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. \n" ); document.write( "What is the lower limit of the 90% confidence interval?::0.71-0.05 = 0.66 \n" ); document.write( "What is the upper limit of the 90% confidence interval?::0.71+0.05 = 0.76\r \n" ); document.write( "\n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " \n" ); document.write( " |