document.write( "Question 51344: solve this equation or formula for the specified variable.\r
\n" ); document.write( "\n" ); document.write( "3(2j-k)=108, for j
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Algebra.Com's Answer #34278 by rapaljer(4671)\"\" \"About 
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3(2j-k)=108\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 3:
\n" ); document.write( "(2j-k)=36\r
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\n" ); document.write( "\n" ); document.write( "Add k to each side to undo the -k:
\n" ); document.write( "2j = 36 + k\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 2:
\n" ); document.write( "\"j+=+%2836%2Bk%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "This can also be written:
\n" ); document.write( "\"j+=+36%2F2+%2B+k%2F2\"
\n" ); document.write( "\"j+=+18+%2B+k%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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