document.write( "Question 512875: the dimensions of a rectangle with a perimeter of 88 inches and the length one inch less than 4 times the width. \n" ); document.write( "

Algebra.Com's Answer #342765 by josmiceli(19441) $\"\"$ $\"About$

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The formula for perimeter:
\n" ); document.write( " $\"+P+=+2W+%2B+2L+\"$
\n" ); document.write( "given:
\n" ); document.write( " $\"+2W+%2B+2L+=+88+\"$
\n" ); document.write( "(1) $\"+w+%2B+L++=+44+\"$
\n" ); document.write( "also
\n" ); document.write( "(2) $\"+L+=+4W+-+1+\"$
\n" ); document.write( "---------------
\n" ); document.write( "(1) $\"+L+=+44+-+W+\"$
\n" ); document.write( "Substitute this into (2)
\n" ); document.write( "(2) $\"+44+-+W+=+4W+-+1+\"$
\n" ); document.write( "(2) $\"+5W+=+44+%2B+1+\"$
\n" ); document.write( "(2) $\"+5W+=+45+\"$
\n" ); document.write( "(2) $\"+W+=+9+\"$
\n" ); document.write( "and, since
\n" ); document.write( "(1) $\"+L+=+44+-+W+\"$
\n" ); document.write( "(1) $\"+L+=+44+-+9+\"$
\n" ); document.write( "(1) $\"+L+=+35+\"$
\n" ); document.write( "The dimensions are 9\" x 35\"
\n" ); document.write( "check:
\n" ); document.write( " $\"+P+=+2W+%2B+2L+\"$
\n" ); document.write( " $\"+P+=+2%2A9+%2B+2%2A35+\"$
\n" ); document.write( " $\"+P+=+18+%2B+70+\"$
\n" ); document.write( " $\"+P+=+88+\"$
\n" ); document.write( "OK \n" ); document.write( "

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