document.write( "Question 512854: The length of a rectangle is 6 feet more than its width. What are the dimensions
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document.write( "of the rectangle if the perimeter is 44 feet?
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Algebra.Com's Answer #342754 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Perimeter = 44 feet \n" ); document.write( "Length = l=w+6 \n" ); document.write( "Width = w \n" ); document.write( "Perimeter of a Rectangle = length + length + width + width \n" ); document.write( "Perimeter of a Rectangle = 2l + 2w \n" ); document.write( "44=2(w+6)+2w \n" ); document.write( "44=2w+12+2w \n" ); document.write( "44-12=4w \n" ); document.write( "32=4w \n" ); document.write( "32/4=4w/4 \n" ); document.write( "8=w \n" ); document.write( "w=8 \n" ); document.write( "Length = l=w+6=4+6=10\r \n" ); document.write( "\n" ); document.write( "Dimensions of the rectangle \n" ); document.write( "Length=10 \n" ); document.write( "Width=8 \n" ); document.write( "Perimeter=44 \n" ); document.write( " \n" ); document.write( " |