document.write( "Question 512848: What is the equation in slop-intercept form of the line perpendicular to the segment between (1,3) and (5,5) and passing through (3,4)?\r
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Algebra.Com's Answer #342753 by mananth(16946)\"\" \"About 
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x1 y1 x2 y2
\n" ); document.write( "1 3 5 5
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\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( 5 - 3 )/( 5 - 1 )
\n" ); document.write( "( 2 / 4 )
\n" ); document.write( "m= 1/ 2 \r
\n" ); document.write( "\n" ); document.write( "the perpendivular line will have a slope which is negative reciprocal of this segment.\r
\n" ); document.write( "\n" ); document.write( "so m = -2\r
\n" ); document.write( "\n" ); document.write( "plug m=-2 & (3,4) in y=mx+b\r
\n" ); document.write( "\n" ); document.write( "4=-2*3+b
\n" ); document.write( "5=-6+b
\n" ); document.write( "b=10\r
\n" ); document.write( "\n" ); document.write( "The equation will be y=-2x+10\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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