document.write( "Question 51327This question is from textbook college algebra
\n" ); document.write( ": Please help...got stuck on this problem for long time...thank you!!\r
\n" ); document.write( "\n" ); document.write( "\"Fencing Dog Pens\" Clint is constructing 2 adjacent rectangular dog pens. Each pen will be three times as it is wide, and the pens will share a common long side. If Clint has 65ft of fencing, what are the dimensions of each pen??
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Algebra.Com's Answer #34274 by Earlsdon(6294)\"\" \"About 
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I assume that you meant to write...\"Each pen will be three times as long as it is wide,...\"
\n" ); document.write( "If we let the width be W, then the length of each pen will be: L = 3W.\r
\n" ); document.write( "\n" ); document.write( "From the problem description, the two adjacent pens will have three long sides and four short sides.
\n" ); document.write( "Each long side will be 3W in length and there are three of these,
\n" ); document.write( "so we have 3(3W) = 9W. This is the total of the lengths.
\n" ); document.write( "The short sides (Widths) wll each be W in length and there are four of these, so we have 4(W) = 4W This the total of the widths.
\n" ); document.write( "Adding up all of these, we get:
\n" ); document.write( "9W + 4W = 13W and this is equal to the total length of the fence (perimeter) of 65 feet.
\n" ); document.write( "13W = 65 Divide both sides by 13.
\n" ); document.write( "W = 5 feet.
\n" ); document.write( "This is the length of each width, but there are four of these, so we have the total for the widths is: 4(5) = 20 feet.
\n" ); document.write( "The length, L = 3W = 3(5) = 15 feet
\n" ); document.write( "The three lengths is then: 3(15) = 45 feet.\r
\n" ); document.write( "\n" ); document.write( "Each pen measures: (L X W) = 15 ft. by 5 ft.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "Adding up the the total widths and the total lengths, we get: 20 ft + 45 ft = 65 ft.\r
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