document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=512615>Question 512615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Brian is putting a fence around his garden. The garden is 4ft wide and 7ft long. He has 10yd of fence. Does he have enough fence to put a fence all the way around his garden? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342670 by </B><A HREF=/tutors/aboutme.mpl?userid=rosey51235><B>rosey51235(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rosey51235><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rosey51235><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes, he does have enough fencing. <BR>\n" );
document.write( "We're talking perimeter, and if the garden is 4ft. X 7ft, we're just doubling the numbers and adding them. 8+14=22ft, which is the perimeter of this garden.<BR>\n" );
document.write( "Now remember, the problem said 10YDS. of fence, so we have to transalate that to feet. <BR>\n" );
document.write( "There are 3 feet in a yard, so 10yds. X3=30ft. of fencing. <BR>\n" );
document.write( "He has 30ft. and a 22ft perimeter garden, thus he has more than enough to surround the garden! \r<BR>\n" );
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document.write( "Hope I helped! :)<BR>\n" );
document.write( "(Also, I'm not a great speller, I apologize for any errors.)<BR>\n" );
document.write( "-Rosey </SPAN>\n" );
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