document.write( "Question 512428: jack is twice as old as lacy.in three years the sum of their ages will be fifty four. how old are they now \n" ); document.write( "

Algebra.Com's Answer #342627 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"j\"$ = Jack's age now
\n" ); document.write( "Let $\"y\"$ = Lacy's age now
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"+j+=+2y+\"$
\n" ); document.write( "(2) $\"+j+%2B+3+%2B+y+%2B+3+=+54+\"$
\n" ); document.write( "---------------------
\n" ); document.write( "(2) $\"+j+%2B+y+=+48+\"$
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+2y+%2B+y+=+48+\"$
\n" ); document.write( "(2) $\"+3y+=+48+\"$
\n" ); document.write( "(2) $\"+y+=+16+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+j+=+2y+\"$
\n" ); document.write( "(1) $\"+j+=+32+\"$
\n" ); document.write( "Jack is 32 and Lacy is 16 \n" ); document.write( "

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