document.write( "Question 512298: \"+x%5E2%2B7x-5=+0+\"\r
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Algebra.Com's Answer #342595 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\"+x%5E2%2B7x-5=+0+\"
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document.write( "Put a 1 coefficient on the x² term:\r\n" );
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document.write( "\"1x%5E2%2B7x-5=+0+\"\r\n" );
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document.write( "Compare to\r\n" );
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document.write( "\"ax%5E2%2Bbx%2Bc=+0+\"\r\n" );
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document.write( "and get a=1, b=7, c=-5 and substitute in:\r\n" );
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r\n" );
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document.write( "\"x+=+%28-7+%2B-+sqrt%28+7%5E2-4%2A1%2A%28-5%29+%29%29%2F%282%2A1%29+\"\r\n" );
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document.write( "\"x+=+%28-7+%2B-+sqrt%28+49%2B20+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-7+%2B-+sqrt%2869+%29%29%2F2+\"\r\n" );
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document.write( "Edwin

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