document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51238>Question 51238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need help with this problem please...\r<BR>\n" );
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document.write( "write an equation in slope-intercept form that satisfies each condition.<BR>\n" );
document.write( "passes through (2,-1) and is perpendicularto 3x-y=-3\r<BR>\n" );
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document.write( "i wrote it like 3(2)-(-1)=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34259 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST YOU NEED TO FIND THE LINE EQUATION FOR 3X-Y=-3 WHICH IS -Y=-3X-3 OR\r<BR>\n" );
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document.write( "Y=3X+3 THIS GIVE YOU THE SLOPE OF THIS EQUATION AS -3 & THE Y INTERCEPT OF 3 \r<BR>\n" );
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document.write( "THUS THE PERPENDICULAR LINE RUNNING THROUGH (2,-1) HAS A SLOPE OF -1/3 \r<BR>\n" );
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document.write( "-1=-1/3*2+B THEN -1=-2/3+B OR -1+2/3=B OR B=-1/3 <BR>\n" );
document.write( "THUS THE EQUATION FOR THE LINE THROUGH (2,-1) AND PERPENDICULAR TO 3X-Y=-3 IS Y=-1/3X-1/3  </SPAN>\n" );
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