document.write( "Question 512188: A Commercial jet can fly 500 mph in calm air. Traveling with the wids of the jet stream, the plane flew 2420 miles in the same amount of time as it takes to fly 1580 miles against the jet stream. What is the rate of the speed of the jet stream? \n" ); document.write( "
Algebra.Com's Answer #342578 by mananth(16946)\"\" \"About 
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plane speed = 500 mph
\n" ); document.write( "wind speed = x mph
\n" ); document.write( "speed against wind 500 - x 11.7
\n" ); document.write( "speed with current 500 + x
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\n" ); document.write( "Distance against current 1580 m
\n" ); document.write( "Distance with current 2420 m
\n" ); document.write( "
\n" ); document.write( "t=d/r time against = time with
\n" ); document.write( "1580/( 500 -x)= 2420 /(500 + x )
\n" ); document.write( "1580 ( 500 + x )= 2420 (500-x)
\n" ); document.write( "790000 + 1580 x = 1210000 - 2420 x
\n" ); document.write( "2420 x 1580 x = 420000
\n" ); document.write( "4000 x = 420000
\n" ); document.write( "/ 4000
\n" ); document.write( "x = 105 mph wind speed
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