document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=512184>Question 512184</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following system by substitution \r<BR>\n" );
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document.write( "y=2x+3<BR>\n" );
document.write( "5x-2y+ -8\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #342576 by </B><A HREF=/tutors/aboutme.mpl?userid=10301650><B>10301650(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=10301650><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=10301650><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=342576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=2x+3<BR>\n" );
document.write( "5x-2y -8<BR>\n" );
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document.write( "---: use the second given to find the answer for x<BR>\n" );
document.write( " 5x-2y-8<BR>\n" );
document.write( "---: then substitute the variable y into 2x+3 (the 1st given)<BR>\n" );
document.write( "5x-2(2x+3)-8=0<BR>\n" );
document.write( "5x-4x+6-8=0<BR>\n" );
document.write( "x-2=0<BR>\n" );
document.write( "x=2 (ANSWER)<BR>\n" );
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document.write( "---: now lets solve for the y. use the 1st the 1st given<BR>\n" );
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document.write( "y=2x+3<BR>\n" );
document.write( "y=2(2)+3<BR>\n" );
document.write( "y=4+3<BR>\n" );
document.write( "y=7 (ANSWER)<BR>\n" );
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