document.write( "Question 511410: How much water should be added to 100 liters of 90% alcohol concentration to dilute it to 75% alcohol concentration? \n" ); document.write( "
Algebra.Com's Answer #342567 by Maths68(1474)\"\" \"About 
You can put this solution on YOUR website!
Solution A
\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration =0% =0 (It is pure water so concentration of Acohoal wil be zero)\r
\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 100
\n" ); document.write( "Concentration =90% = 0.9\r
\n" ); document.write( "\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount =100+x
\n" ); document.write( "Concentration =75%=0.75\r
\n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant\r
\n" ); document.write( "\n" ); document.write( "(0)x+(0.9)(100)=(100+x)(0.75)
\n" ); document.write( "90=75+0.75x
\n" ); document.write( "90-75=0.75x
\n" ); document.write( "15=0.75x
\n" ); document.write( "15/0.075=x
\n" ); document.write( "20=x\r
\n" ); document.write( "\n" ); document.write( "Solution A
\n" ); document.write( "Amount = x =20 liters
\n" ); document.write( "Concentration =0% =0 (It is pure water so concentration of Acohoal wil be zero)\r
\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 100
\n" ); document.write( "Concentration =90% = 0.9\r
\n" ); document.write( "\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount =100+x =100+20=120 liters
\n" ); document.write( "Concentration =75%=0.75\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Result
\n" ); document.write( "---------
\n" ); document.write( "20 liters water should be added to 100 liters of 90% alcohol concentration to dilute it to 75% alcohol concentration.
\n" ); document.write( "
\n" ); document.write( "
\n" );