document.write( "Question 511886: How many liters of a 40% and 80% acids must be mixed in order to make 20 liters of a 55% acid solution?\r
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\n" ); document.write( "\n" ); document.write( "A 12 liter mixture is 60% alcohol. if 8 liters of a 25% alcohol mixture are added, what percent mixture will be formed.
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Algebra.Com's Answer #342566 by Maths68(1474)\"\" \"About 
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(1)
\n" ); document.write( "How many liters of a 40% and 80% acids must be mixed in order to make 20 liters of a 55% acid solution? \r
\n" ); document.write( "\n" ); document.write( "Solution A
\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration =40% = 0.4\r
\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 20-x
\n" ); document.write( "Concentration =80% = 0.8\r
\n" ); document.write( "\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount =20
\n" ); document.write( "Concentration =55%=0.55\r
\n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant\r
\n" ); document.write( "\n" ); document.write( "(0.4)x+(0.8)(20-x)=(20)(0.55)
\n" ); document.write( "0.4x+16-0.8x=11
\n" ); document.write( "0.4x-0.8x=11-16
\n" ); document.write( "-0.4x=-5
\n" ); document.write( "-0.4x/-0.4=-5/-0.4
\n" ); document.write( "x=12.5\r
\n" ); document.write( "\n" ); document.write( "Solution A
\n" ); document.write( "Amount = x =12.5 liters
\n" ); document.write( "Concentration =40% = 0.4\r
\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 20-x =20-12.5=7.5 liters
\n" ); document.write( "Concentration =80% = 0.8\r
\n" ); document.write( "\n" ); document.write( "Result
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\n" ); document.write( "12.5 liters of a 40% and 7.5 liters of 80% acids must be mixed in order to make 20 liters of a 55% acid solution
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\n" ); document.write( "(2)
\n" ); document.write( "A 12 liter mixture is 60% alcohol. if 8 liters of a 25% alcohol mixture are added, what percent mixture will be formed.\r
\n" ); document.write( "\n" ); document.write( "Solution A
\n" ); document.write( "Amount =12 liters
\n" ); document.write( "Concentration =60% = 0.6\r
\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 8 liters
\n" ); document.write( "Concentration =25% = 0.25\r
\n" ); document.write( "\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount =(8+12)=20 liters
\n" ); document.write( "Concentration =x\r
\n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant
\n" ); document.write( "(12*0.6)+(8)(0.25)=20x
\n" ); document.write( "7.2+2=20x
\n" ); document.write( "9.2=20x
\n" ); document.write( "9.2/20=20x/20
\n" ); document.write( "0.46=x
\n" ); document.write( "x=0.46
\n" ); document.write( "x=46/100= 46%\r
\n" ); document.write( "\n" ); document.write( "Result
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\n" ); document.write( "If we add 12 liter 60% alcohol solution to 8 liters of a 25% alcohol solution, a mixture of 20 liters of 46% alcohol will be formed.
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