document.write( "Question 512138: There are 12 women and 5 men. A committee of 7 women and 4 men is to be chosen. How many different committee can be formed? \n" ); document.write( "
Algebra.Com's Answer #342542 by SUNIL1987MAURYA(7)![]() ![]() You can put this solution on YOUR website! no. of choices to choose women=(12)C(7) \n" ); document.write( "=(12*11*10*9*8)/(5*4*3*2*1) \n" ); document.write( "=792 \n" ); document.write( "no. of choices to choose men=(5)C(4) \n" ); document.write( "=5 \n" ); document.write( "total no. of different committees=792*5 \n" ); document.write( "=3960 \n" ); document.write( " |