document.write( "Question 512129: Jose left the White House and drove toward the recycling plant at an average speed of 40 km/h. Rob left some time later driving in the same direction at an average speed of 48 km/h. After driving for five hours Rob caught up with Jose. How long did Jose drive before Rob caught up? \n" ); document.write( "
Algebra.Com's Answer #342540 by josmiceli(19441)\"\" \"About 
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Let \"+d%5B1%5D+\" = Jose's head start in km
\n" ); document.write( "Let \"+t%5B1%5D+\" = time between Jose's leaving and Rob's leaving
\n" ); document.write( "After Rob leaves, Jose travels \"+40%2A5+=+200+\" km
\n" ); document.write( "During the same time, Rob travels \"+48%2A5+=+240+\" km
\n" ); document.write( "\"+d%5B1%5D+=+240+-+200+\"
\n" ); document.write( "\"+d%5B1%5D+=+40+\" km
\n" ); document.write( " Jose drove for \"+t%5B1%5D+=+40%2F40+\", or 1 hour until Rob left
\n" ); document.write( "In all, Jose drove for \"+1+%2B+5+=+6+\" hours
\n" ); document.write( "--------------------
\n" ); document.write( "check answer:
\n" ); document.write( "Rob's equation:
\n" ); document.write( "\"+d+=+48%2A5+\"
\n" ); document.write( "\"+d+=+240+\"
\n" ); document.write( "Jose's equation:
\n" ); document.write( "\"+d+=+40%2A6+\"
\n" ); document.write( "\"+d+=+240+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );