document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51316>Question 51316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We are supposed to factor completely. The problem is:<BR>\n" );
document.write( "4xcubed plus 12xsquared minus 8x equals\r<BR>\n" );
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document.write( "I have it factored to 4x(xsquared + 3x - 2) I know it has to factor down to something like, 4x(x+ )(x- )I'm stuck..... Any help would so be appreciated! Thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34254 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4X^3+12X^2+8X=0 OR 4X(X^2+3X+2=0 OR 4X=0 OR X=0 & (X+2)(X+1)=0 OR X+2=0 OR<BR>\n" );
document.write( "X=-2 & X+1=0 OR X=-1\r<BR>\n" );
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document.write( "PROOF 4*0^3+12*0^2+8*0=0 OR 0+0+0=0 OR 0=0 <BR>\n" );
document.write( "4(-2)^3+12(-2^2)+8*-2=0 OR 4*-8+12*4-16=0 OR -32+48-16=0 OR 0=0<BR>\n" );
document.write( "4(-1)^3+12(-1^2)+8*-1=0 OR 4*-1+12*1-8=0 OR -4+12-8=0 OR 0=0\r<BR>\n" );
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